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If they key already exists within the tree, the old data will be freed with the destroy function if provided and replaced with the new value The tree is then automatically balanced after the new node is inserted void g_tree_insert (GTree *tree, gpointer key, gpointer value); You can also use g_tree_replace() to add a node to a binary tree The only difference between this function and g_tree_insert() is that if the key already exists within the tree, the key itself will also be replaced If the key does not already exist, it will be inserted into a new position in the tree, and the tree will automatically be balanced At times, you may need to know basic information about the structure of the tree For example, you can get the number of nodes with g_tree_nnodes() and the current height of the tree with g_tree_height().

namespace IntegrationTests { [TestFixture] public class VisitorRepositoryTester { [SetUp] public void Setup() { new DatabaseTester().CreateDatabaseSchmea(); } [Test] public void When_saving_should_write_to_database() { var config = new DataConfig(); Configures config.PerformStartup(); NHibernate config.StartSession(); var visitor = new Visitor Creates new { Visitor Browser = "1", IpAddress = "2", LoginName = "3", PathAndQuerystring = "4", VisitDate = new DateTime(2000, 1, 1) }; var repository = new VisitorRepository(); repository.Save(visitor); config.EndSession(); config.StartSession();

15.2. Message Authentication Codes (MACs)

With these two pieces of information, you should be able to figure out the general structure of the tree To retrieve the value associated with a key in a binary tree, you need to call g_tree_lookup() If the key is found, the associated value will be returned Otherwise, this function will return NULL gpointer g_tree_lookup (GTree *tree, gconstpointer key);.

ISession session = new SessionCache() Reloads Visitor .GetSession(); var loadedVisitor = session.Load<Visitor>(visitor.Id); Assert.That(loadedVisitor, Is.Not.Null); Assert.That(loadedVisitor.Browser, Is.EqualTo("1")); Assert.That(loadedVisitor.IpAddress, Is.EqualTo("2")); Assert.That(loadedVisitor.LoginName, Is.EqualTo("3")); Assert.That(loadedVisitor .PathAndQuerystring, Is.EqualTo("4")); Assert.That(loadedVisitor.VisitDate, Is.EqualTo(new DateTime(2000, 1, 1))); } [Test] public void Should_get_two_most_recent_visitors() { var config = new DataConfig(); config.PerformStartup();

Alternatively, you can use g_tree_lookup_extended(), which will also return pointers to the original key and its associated value by reference This function will return TRUE if the key was found This brings us to one big advantage of binary trees Since the tree is automatically balanced, finding a key is very fast, even if there are a large number of elements in the list In the worst case, it will take the number of comparisons equal to the height of the tree to find the node If you need to perform some operation on every node in a binary tree, you need to specify a traversal function to g_tree_foreach() The GTraverseFunc prototype accepts three gpointer parameters corresponding to a key, its associated value, and the user data from g_tree_foreach() In order to stop the traversal, you should return TRUE from the function.

Visitor visitor1 = CreateVisitor(new DateTime(2000, 1, 1)); Visitor visitor2 = CreateVisitor(new DateTime(2000, 1, 2)); Visitor visitor3 = CreateVisitor(new DateTime(2000, 1, 3)); config.StartSession(); using ( ISession session1 = new SessionCache().GetSession()) { session1.SaveOrUpdate(visitor1); session1.SaveOrUpdate(visitor2); session1.SaveOrUpdate(visitor3); session1.Flush(); config.EndSession(); } config.StartSession(); var repository = new VisitorRepository(); Visitor[] recentVisitors = repository.GetRecentVisitors(2); config.EndSession(); Assert.That(recentVisitors.Length, Is.EqualTo(2)); IEnumerable<Guid> idList = recentVisitors.Select(x => x.Id); Assert.That(idList.Contains(visitor3.Id), Is.True); Assert.That(idList.Contains(visitor2.Id), Is.True); Assert.That(idList.Contains(visitor1.Id), Is.False); } private Visitor CreateVisitor(DateTime visitDate) { return new Visitor { Browser = "1", IpAddress = "2", LoginName = "3", PathAndQuerystring = "4", VisitDate = visitDate }; } } }

MACs can be used to determine if a message originated from a principal that has possession of a secret key. In particular, Alice and Bob may share a key, k, and Alice may use that key to compute a MAC on a message, M, which we denote as t = MAC(M,k). Alice can then transmit M and t to Bob. The value t is often referred to as a tag. Let M' be the message that Bob receives and t' be the corresponding MAC that he receives. If Mallory attempts to modify either M or t, Bob can detect any potential tampering by checking whether t' = MAC(M',k). If the equality holds true, it means (with overwhelmingly high probability) that either the message and signature were not tampered with (M' = M and t' = t) or that Mallory knows k.